(x^2-3x)-(2x^2-5x)=0

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Solution for (x^2-3x)-(2x^2-5x)=0 equation:


Simplifying
(x2 + -3x) + -1(2x2 + -5x) = 0

Reorder the terms:
(-3x + x2) + -1(2x2 + -5x) = 0

Remove parenthesis around (-3x + x2)
-3x + x2 + -1(2x2 + -5x) = 0

Reorder the terms:
-3x + x2 + -1(-5x + 2x2) = 0
-3x + x2 + (-5x * -1 + 2x2 * -1) = 0
-3x + x2 + (5x + -2x2) = 0

Reorder the terms:
-3x + 5x + x2 + -2x2 = 0

Combine like terms: -3x + 5x = 2x
2x + x2 + -2x2 = 0

Combine like terms: x2 + -2x2 = -1x2
2x + -1x2 = 0

Solving
2x + -1x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(2 + -1x) = 0

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {0, 2}

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